Answer:
<h2>
AC = 36.01</h2>
Step-by-step explanation:
Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.
From ΔADB, AB² = AD²+BD²
Given AB = 24 and AD = 16
BD² = AB² - AD²
BD² = 24²-16²
BD² = 576-256
BD² = 320
BD = 
BD = 17.9
from ΔABC, AC² = AB²+BC²
SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;
(AD+DC)² = AB²+ (BD² + DC²)
Given AD = 16, AB = 24 and BD = 17.9, on substituting
(16+DC)² = 24²+17.9²+ DC²
256+32DC+DC² = 24²+17.9²+ DC²
256+32DC = 24²+17.9²
32DC = 24²+17.9² - 256
32DC = 640.41
DC = 
DC = 20.01
Remember that AC = AD+DC
AC = 16+20.01
AC = 36.01
Then my house will be in the south because thats the only one that is left
2 pieces of squid = $3.50
Therefore 1 piece of squid = $1.75 (3.50÷2)
1 piece of eel = $3.25
3 pieces of tuna = $6.75
Therefore 1 piece of tuna = $2.25 (6.75÷3)
4 pieces of crab = $8.00
Therefore 1 piece of crab = $2 (8÷4)
Put them in order of price and you get
$1.75 , $2 , $2.25 , $3.25
squid,crab,tuna,eel
Are you asking for the expression?
If so, you plug into the format (x - h)² + (y - k)² = r² where (h, k) is the center and r is the radius.
(x + 2.5)² + (y + 4.4)² = (7/4)²
Simplify to get your equation and answer:
(x + 2.5)² + (y + 4.4)² = 49/16
Answer:
Therefore the area of the quadrilateral =35 cm²
Step-by-step explanation:
Given, the length of one of diagonal of quadrilateral is 10 cm and perpendicular drawn from the opposite vertices to this diagonal are the length of 2.8 cm and 4.2 cm.
A diagonal divided a quadrilateral into two triangle.
Therefore the area of the quadrilateral
= sum of the area of the triangles
cm² [ area of a triangle
]
=35 cm²
