The equation of circle is
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117
Answer:
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Step-by-step explanation:
Answer:
6 seconds
Step-by-step explanation:
h(x)=-(x-2)^2+16
We want h(x) to be 0 ( that is when the ball hits the ground)
0 = -(x-2)^2+16
Subtract 16 from each side
-16 = -(x-2)^2+16-16
-16 = -(x-2)^2
Divide by -1
16 = (x-2)^2
Take the square root of each side
sqrt(16) = sqrt((x-2)^2)
±4 = x-2
Add 2 to each side
2±4 = x-2+2
2±4 =x
2+4 = x 2-4 = x
6 =x -2 =x
Time cannot be negative so x=6
Looks like 14.4 because you have to add them all together and divide by the total numbers
(20+22+10+5+15)/ 5
