If a point in Quadrant I is reflected across the x-axis, where is the reflection located?

Are the expressions 3{y+1} and 3y+3 equivalent for any value? explain

andre [41]

Answer:

Yes

Step-by-step explanation:

The distributive property states that a(b+c) = ab+ac. Working out the first equation, we see that 3(y+1) is 3y+3. Because the second equation is 3y+3, they are also equal.

8 0

4 years ago

Read 2 more answers

The scale of scores for an IQ test are approximately normal with mean 100 and standard deviation 15. The organization MENSA, whi

Zina [86]

Answer:

B) 47.5%

Step-by-step explanation:

Refer to the normal distribution chart attached. If 130 is 2 standard deviations higher than the mean (ignore the numbers beneath the percentages), then by the empirical rule, this means that 34%+13.5%=47.5% of adults are between IQs of 100 and 130. Therefore, option B is correct.

5 0

3 years ago

What is the VOLUME of this figure?<br> 9 cm<br> 7 cm<br> 8 cm<br> 10 cm<br> 12 cm

valentina_108 [34]

Answer:

1390 cm^3

Step-by-step explanation:

9 x 7 x 10 = 630 cm^3 for the rectang prism top

area * 10 for the bottom

8 x ( 12 + 7)/2 * 10 = 760 cm^3 for the trap base

total = 1390 cm^3

6 0

2 years ago

What is the solution to the system of equations?

Dovator [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}$

$\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}$

$x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10$

4 0

3 years ago

2.6.PS-

mojhsa [17]

Answer:

Step-by-step explanation:

5 bags= $12.50

1= ?

$12.50*1= 12.50

$12.50/5= $2.5

$2.5*5=$12.5

$2.5*3= $7.5

3 bags= $7.5

8 0

3 years ago