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cestrela7 [59]
3 years ago
12

The length of a rectangle is 3 centimeters less than five times its width. Its area is 14 square centimeters. Find the dimension

s of the rectangle. W= L=​
Mathematics
1 answer:
katrin [286]3 years ago
3 0

Step-by-step explanation:

Let breadth =x

Length=5x-3

As we know that in a rectangle

\boxed{\sf Area=lb}

  • Substitute the values

{:}\hookrightarrow\sf x (5x-3)=14

{:}\hookrightarrow\sf 5x^2-3x=14

{:}\hookrightarrow\sf 5x^2-3x-14=0

{:}\hookrightarrow\sf 5x^2-10x+7x-14=0

{:}\hookrightarrow\sf 5x (x-2)+7 (x-2)=0

{:}\hookrightarrow\sf (x-2)(5x+7)=0

{:}\hookrightarrow\sf x-2=0\quad or\quad 5x+7=0

{:}\hookrightarrow\sf x=2\:or\:x=\dfrac {-7}{5}

  • Ignore negative value

{:}\hookrightarrow\sf Breadth =2cm

{:}\hookrightarrow\sf Length=5 (2)-3=10-3=7cm

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Let x be the width 
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(2x-3)(x)=14
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Since we know that negative values cannot exist in distance, we have to take 7/2 to as the correct answer. 

The width would be 3.5 yards 
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If f(x) = 12x+2, then f^-1(x) =??​
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Step-by-step explanation:

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