Answer:
There are two choices for angle Y:
for
,
for
.
Step-by-step explanation:
There are mistakes in the statement, correct form is now described:
<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>
The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:
(1)
If we know that
,
and
, then we have the following second order polynomial:

(2)
By the Quadratic Formula we have the following result:

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:



1) 
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-15.193%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)

2) 
![Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]](https://tex.z-dn.net/?f=Y%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B18%5E%7B2%7D%2B14%5E%7B2%7D-8.424%5E%7B2%7D%7D%7B2%5Ccdot%20%2818%29%5Ccdot%20%2814%29%7D%20%5Cright%5D)

There are two choices for angle Y:
for
,
for
.
Answer:
$255
Step-by-step explanation:
Using the information provided, in order to find Marco's starting balance we simply need to add all of his transaction costs together. Once we have this value we simply add it to his ending balance amount which will give us the total dollar value of his starting balance.
20 + 22 + 13 + 39 + 34 + 15 + 31 = 174
174 + 81 = $255
Finally, we can see that Marco's starting balance was a total of $255
9x² - 12x + 4
write the equation with two middle terms that multiply to give 36
9x² - 6x - 6x + 4
by factorisation
3x(3x - 2) - 2(3x - 2)
(3x - 2)²
Thus OPTION A
Answer:
m<BAC = 60°
Step-by-step explanation:
Theorem:
In a triangle, the measure of an exterior angle equals the sum of the measures of its remote interior angles.
m<ACD = m<A + m<B
130° = m<A + 70°
m<A = 60°
m<BAC = 60°
(5y-10)(2y-6)
10y-30y-20y+60
-40y+60
Hope that helps!