Answer:
22 more gallons.
Step-by-step explanation:
Given:
Car A's fuel efficiency is 34 miles per gallon of gasoline.
Car B's fuel efficiency is 23 miles per gallon of gasoline.
Question asked:
At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?
Solution:
<u>Car A's fuel efficiency is 34 miles per gallon of gasoline.</u>
<u>By unitary method:</u>
Car A can travel 34 miles in = 1 gallon
Car A can travel 1 mile in = ![\frac{1}{34} \ gallon](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B34%7D%20%5C%20gallon)
Car A can travel 1564 miles in = ![\frac{1}{34} \times1564=46\ gallons](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B34%7D%20%5Ctimes1564%3D46%5C%20gallons)
<u>Car B's fuel efficiency is 23 miles per gallon of gasoline.</u>
Car B can travel 23 miles in = 1 gallon
Car B can travel 1 mile in = ![\frac{1}{23} \ gallon](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B23%7D%20%5C%20gallon)
Car B can travel 1564 mile in = ![\frac{1}{23} \times1564=68\ gallons](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B23%7D%20%5Ctimes1564%3D68%5C%20gallons)
We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.
Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.
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