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3 years ago

A $400 table is on sale for 33% off. There is a 6.8% sales tax. How would you find the final price of the table?

Mathematics

2 answers:

katrin [286]3 years ago

5 0

Answer:

$286.22

Step-by-step explanation:

Price without sales tax:

400*0.33=132

400-132=268

Price with sales tax:

268*0.068=18.224—round to 18.22

268+18.22=286.22

Rasek [7]3 years ago

4 0

Answer:

260

Step-by-step explanation:

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zhenek [66]

Answer:

Step-by-step explanation:

length = x +x + 2 = 2x + 2

Width = 2+ x

Area of rectangle = length *width

(x +2)(2x + 2) = 110

Use FOIL method

x*2x + x*2 + 2*2x + 2*2 = 110

2x² + 2x + 4x + 4 - 110 = 0 {Combine like terms}

2x² +6x - 106 = 0

a = 2 ; b = 6 ; c = -106

b² - 4ac = 6² - 4*2*(-106)

= 36 + 848

= 884

$\sqrt{b^{2}-4ac}=\sqrt{884}= 29.73$

$x =\dfrac{-b+\sqrt{b^{2}-4ac}}{2a} \ ; \ x==\dfrac{-b-\sqrt{b^{2}-4ac}}{2a}\\\\x = \dfrac{-6+29.73}{2*2} \ ; \ x =\dfrac{-6-29.73}{2*2} \ this \ is \ ignored \ as \ it \ is \ negative\\\\x=\dfrac{23.73}{4};$

x = 5.93 m

5 0

2 years ago

Before being simplified, the instructions for computing income tax in Country R were to add 2 percent of one’s annual income to

Vedmedyk [2.9K]

Answer:

Option C)

$50 + \dfrac{I}{40}$

Step-by-step explanation:

We are given the following in the question:

I is the annual income of a person in a country R

2 percent of one’s annual income =

$\dfrac{2}{100}\times I = 0.02I$

1 percent of one’s annual income =

$\dfrac{1}{100}\times I = 0.01I$

Average of 100 units of Country R’s currency and 1 percent of one’s annual income.

$=\dfrac{0.01I + 100}{2}$

Income tax =

2 percent of one’s annual income + Average of 100 units of Country R’s currency and 1 percent of one’s annual income.

$= 0.02I + \dfrac{100+0.01I}{2}\\\\=50 + \dfrac{0.04I + 0.01I}{2}\\\\=50 + \dfrac{0.05I}{2}\\\\= 50 + \dfrac{I}{40}$

Thus, income tax is given by

Option C)

$50 + \dfrac{I}{40}$

6 0

2 years ago

What property is this ? a + (b + c) = (a + b) + c

aev [14]

Associative property

4 0

2 years ago

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Find square root of 82369 by division method step by step

Lina20 [59]

Answer:

I think this ans may help you

3 0

3 years ago

An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu

exis [7]

Take the derivative with respect to t
$- w \sin(wt) + \sqrt{8} w cos(wt)$
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
$0 = -w \sin(wt) + \sqrt{8} w cos(wt)$
divide by w
$0 =- \sin(wt) + \sqrt{8} cos(wt)$
we add sin(wt) to both sides

$\sin(wt)= \sqrt{8} cos(wt)$
divide both sides by cos(wt)
$\frac{sin(wt)}{cos(wt)}= \sqrt{8} \\ \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\ \\ wt=arctan(2 \sqrt{2)}$ OR $\\$ $wt=arctan( { \frac{1}{ \sqrt{2} } )$
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

$I=cos(2n \pi -2arctan( \sqrt{2} ))$
since 2npi is just the period of cos
$cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 
$
substituting our second soultion we get
$I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))$
since 2npi is the period
$I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}$
so the maximum value = $\frac{1}{3}$
minimum value = $- \frac{1}{3}$

4 0

2 years ago