Answer: 0.345
Step-by-step explanation:
Given : The incomes of families in Newport Harbor are normally distributed with Mean :
and Standard deviation : 
Samples size : n=4
Let x be the random variable that represents the incomes of families in Newport Harbor.
The z-statistic :-

For x= $800,000

By using the standard normal distribution table , we have
The probability that the average income of these 4 families exceeds $800,000 :-

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345
Answer:
-51/4 is greater
Step-by-step explanation:
Answer:
ITS B the second one, 3/2 x 8=12
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
Answer:
yes it is
Step-by-step explanation: