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Lerok [7]
3 years ago
13

How to make 155 using 3 prime numbers(You must multiply)

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
5 is a prime factor of 155.  Dividing 155 by 5, we get 31.  1*5*31 = 155.
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The root x = 1 has multiplicity 3 for the function<br>f(x)=x^3-x^2-x+1<br><br>true or false
Inga [223]
Your answer is true
4 0
3 years ago
Read 2 more answers
Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
RideAnS [48]

Answer:

V=5.333cubit unit

Step-by-step explanation:

this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1

The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z

The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below

V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:

5 0
4 years ago
Bob is on his way home in his car. His drive is 16 miles long. He has finished one-fourth of the drive so far. How far has he dr
Georgia [21]

Answer:

He has driven 16 miles so far

Step-by-step explanation:

The unknown in your equation is the total length of Trey's drive, which we will call "x".

From the problem statement, you know that 12 is three-fourths of x so set up the following equation and solve for "x":

3/4(x) = 12

multiply both sides of the equation by 4/3 to isolate "x":

(4/3)(3/4)(x) = (12)(4/3)

therefore

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7 0
3 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

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3 0
3 years ago
The sum of 2 numbers is 10 the difference is 6 what are the numbers calculator
IgorLugansk [536]
8 & 2

8+2 = 10

8-2 = 6
3 0
4 years ago
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