Ask question

Ask question

All categories

3 years ago

5

Angie makes a spicy salsa by adding red pepper flakes to a chunky tomato mix in proportional amounts. For example she mixes 1/2

teaspoon of red pepper flakes to 2 cups of tomato mix. Represent the relationship between red pepper flakes,in teaspoons,to tomato mix,in cups in two different ways (table,graph,or equation) explain the variables

1 answer:

Nastasia [14]3 years ago

8 0

Answer:

Please read the answer below.

Step-by-step explanation:

1. Let's represent the relationship between red pepper flakes, in teaspoons, to tomato mix, in cups in a table

Red pepper (teaspoons) 1/2 1 1 1/2 2 2 1/2 3 3 1/2 4 4 1/2 5

Tomato mix (cups) 2 4 6 8 10 12 14 16 18 20

2. Let's represent the relationship between red pepper flakes, in teaspoons, to tomato mix, in cups writing a equation:

t = amount of tomato mix cups

r = amount of red pepper flakes teaspoons

As we can see in the table,

<u>t = 4r</u>

You might be interested in

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales

mihalych1998 [28]

Answer:

We conclude that the mean number of calls per salesperson per week is more than 37.

Step-by-step explanation:

We are given that the Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 37 sales calls per week on professors.

To investigate, a random sample of 41 sales representatives reveals that the mean number of calls made last week was 40. The standard deviation of the sample is 5.6 calls.

<em><u>Let </u></em> $\mu$ <em><u> = true mean number of calls per salesperson per week.</u></em>

SO, <u>Null Hypothesis</u>, $H_0$ : $\mu \leq$ 37 {means that the mean number of calls per salesperson per week is less than or equal to 37}

<u>Alternate Hypothesis,</u> $H_A$ : $\mu$ > 37 {means that the mean number of calls per salesperson per week is more than 37}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of calls made last week = 40

s = sample standard deviation = 5.6 calls

n = sample of sale representatives = 41

So, <em><u>test statistics</u></em> = $\frac{40-37}{\frac{5.6}{\sqrt{41} } }$ ~ $t_4_0$

= 3.43

Hence, the value of test statistics is 3.43.

<em>Now at 0.025 significance level, the t table gives critical value of 2.021 at 40 degree of freedom for right-tailed test. Since our test statistics is more than the critical value of t as 3.43 > 2.021, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the mean number of calls per salesperson per week is more than 37.

4 0

3 years ago

Find the radius of a sphere with a volume of 26, 2440 cubic inches

ehidna [41]

Answer:

8.7304 x 1010

Step-by-step explanation:

I think its that >_<

The last 10 is supposed to be on top to the right of the 10

4 0

3 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$

So

$e^{-0.01x} = 0.08$

$\ln{e^{-0.01x}} = \ln{0.08}$

$-0.01x = \ln{0.08}$

$x = -\frac{\ln{0.08}}{0.01}$

$x = 252.6$

Capacity of 252.6 cubic feet per second

5 0

3 years ago

Mr. Bell wants to plant a rectangular garden in his backyard. He has 100 feet of fence to

vovangra [49]

Answer:

The dimensions of the garden are 22.5ft by 27.5ft

Step-by-step explanation:

Here, we want to calculate the dimensions of the garden.

let the length be x ft

we are told that the he wants the length to be 5 feet more than the width;

That means the width will be (x-5) ft

Mathematically;

Since the shape is rectangular, the perimeter will be 2( l + w)

Thus; 2(x + x-5) = 100

2(2x-5) = 100

divide both sides by 2

2x-5 = 50

2x = 50 + 5

2x = 55

x = 55/2

x = 27.5 ft

The width is thus; 27.5ft - 5ft = 22.5ft

the dimensions of the garden are 27.5 ft by 22.5 ft

5 0

3 years ago

N x n x n^4/ n^2<br> write as a single power.

bekas [8.4K]

N^4

1 + 1 + 4 - 2 = 4

Mark brainliest

5 0

2 years ago

Read 2 more answers