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3 years ago

Evaluate the following expression: log2 16 HELPPPPP again

Mathematics

1 answer:

Leni [432]3 years ago

4 0

Answer:

Step-by-step explanation:

log2 (16)

Rewriting 16 as 2^4

log2 ( 2^4)

The log 2 and the 2 as the base cancel

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Which of the following is a polynomial with roots 4, 2i, and −2i?

ivolga24 [154]

Hello,

(x+2i)(x-2i)(x-4)=(x²+4)(x-4)=x^3-4x²+4x-16

Answer C

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3 years ago

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Evaluate the expression 2x + 5 when x = 4<br>

Korolek [52]

Answer:

= 2(4) + 5

= 8 + 5

= 13

5 0

3 years ago

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PLEASE HELP ASAP!!!!!!

Rainbow [258]

Answer:

6/5 units³

Step-by-step explanation:

The volume of the prism is given by the formula

V = Bh

where B is the area of the "base" and h is the height perpendicular to that base. Filling in the given numbers, you have ...

V = (9/5)·(2/3) = 18/15 = 6/5 . . . . units³

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4 years ago

Solve for brainliest

Evgesh-ka [11]

Answer:

7) 9.135x10^10

8) 3.428x10^-2

9) 2.5x10^-7

10) 4x10^10

Step-by-step explanation:

You’re only supposed to have one number to the left of the decimal point in scientific notation.

7) 9.135x10^10

8) 3.428x10^-2

9) 2.5x10^-7

10) 4x10^10

3 0

3 years ago

A geometric sequence has first term 1/9 and common ratio 3. Which is the first term of the sequence which exceeds 1000?

Svetach [21]

$a_{n}= \frac{1}{9} (3)^{n-1}$
(We know this from a=1/9 and r=3)
Simplifying this, we get:
$\frac{1}{9} (3)^{-1} (3)^n$

Since we're finding the first term that exceeds 1000, let's set it equal to 1000.

$\frac{1}{27}(3)^n=1000$
Multiplying both sides by 27
$3^n=27000$

$log_{3}27000=n$

n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
$\frac{1}{27}3^{10}$
=2187

Therefore the first term that exceeds 1000 is 2187, and it is the 10th term

3 0

3 years ago