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Elis [28]
3 years ago
8

Y =3cos (2x-1) +0,3 amplitude

Mathematics
1 answer:
saveliy_v [14]3 years ago
3 0

Answer:

Y

=

3

cos

(

2

x

-

1

)

 

Use the form

to

cos

(

b

x

-

c

)

+

d

to find the variables used to find the amplitude, period, phase shift, and vertical shift.

to

=

3

b

=

2

c

=

1

d

=

0

Find the amplitude

|

to

|

.

Amplitude:

3

Find the period using the formula

2

π

|

b

|

.

Tap for more steps ...

Period:

π

Find the phase shift using the formula

c

b

.

Tap for more steps ...

Phase shift:

1

2

Find the vertical displacement

d

.

Vertical displacement:

0

List the properties of trigonometric functions.

Amplitude:

3

Period:

π

Phase shift:

1

2

(

1

2

on the right)

Vertical displacement:

0

Select some points on the graph.

Tap for more steps ...

x

F

(

x

)

1

2

3

π

4

+

1

2

0

π

2

+

1

2

-

3

3

π

4

+

1

2

0

π

+

1

2

3

The trigonometric function can be drawn using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude:

3

Period:

π

Phase shift:

1

2

(

1

2

on the right)

Vertical displacement:

0

x

F

(

x

)

1

2

3

π

4

+

1

2

0

π

2

+

1

2

-

3

3

π

4

+

1

2

0

π

+

1

2

3Y

=

3

cos

(

2

x

-

1

)

 

Use the form

to

cos

(

b

x

-

c

)

+

d

to find the variables used to find the amplitude, period, phase shift, and vertical shift.

to

=

3

b

=

2

c

=

1

d

=

0

Find the amplitude

|

to

|

.

Amplitude:

3

Find the period using the formula

2

π

|

b

|

.

Tap for more steps ...

Period:

π

Find the phase shift using the formula

c

b

.

Tap for more steps ...

Phase shift:

1

2

Find the vertical displacement

d

.

Vertical displacement:

0

List the properties of trigonometric functions.

Amplitude:

3

Period:

π

Phase shift:

1

2

(

1

2

on the right)

Vertical displacement:

0

Select some points on the graph.

Tap for more steps ...

x

F

(

x

)

1

2

3

π

4

+

1

2

0

π

2

+

1

2

-

3

3

π

4

+

1

2

0

π

+

1

2

3

The trigonometric function can be drawn using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude:

3

Period:

π

Phase shift:

1

2

(

1

2

on the right)

Vertical displacement:

0

x

F

(

x

)

1

2

3

π

4

+

1

2

0

π

2

+

1

+

1

2

0

π

+

1

2

3

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AysviL [449]

The number of pieces The customer will need actually is 38 tiles

The number of tiles in boxes the customer will buy is 45 tiles

Step-by-step explanation:

To solve the problem we will do these steps

1. Change the dimensions of the room from feet to inches

2. Calculate the area of the room

3. Calculate the area of one tile

4. Divide the area of the room by the area of the tile to find the number

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5. Divide the number of tiles by the number of pieces in one box

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∵ The dimensions of the room are 8 feet by 9 feet 6 inches

∵ 1 foot = 12 inches

∴ 8 feet = 8 × 12 = 96 inches

∴ 9 feet 6 inches = 9 × 12 + 6 = 108 + 6 = 114 inches

∴ The dimensions of the sun room are 96" by 114"

The area of a rectangle is length × width

∵ Area of the room = 96 × 114 = 10944 inches²

∵ The dimensions of a tile are 12" by 24"

∴ Area of a tile = 12 × 24 = 288 inches²

∵ The number of tiles = Area room ÷ area tile

∴ The number of tiles = 10944 ÷ 288 = 38 tiles

<em>The number of pieces The customer will need is 38 tiles</em>

<u><em>V.I.N:</em></u>

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∵ 38 ÷ 9 = 4.22

∴ He will need to buy 5 boxes with 45 tiles

<em>The number of tiles in boxes is 45 tiles</em>

Learn more:

You can learn more about the area of some figures in brainly.com/question/4459688

brainly.com/question/4354581

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4 0
4 years ago
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irakobra [83]
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4 0
3 years ago
Read 2 more answers
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borishaifa [10]

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10 x 5 = 50

50 x 5 = 250

250 x 5 = 1250

Answer

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2, 10, 50,250, 1250


7 0
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Helga [31]
<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

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The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

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