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3 years ago

Find the solution to the system of equations y=x-4 and y=4x+2

Mathematics

2 answers:

dmitriy555 [2]3 years ago

7 0

The answer is y=x-4=4x+2

gogolik [260]3 years ago

4 0

The answer will be

I solve by substitution

(-2, -6)

X=-2, y=-6

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You lose 2 points every time you forget to write your name on a test. You have forgotten to write your name 6 times. What intege

coldgirl [10]

A loss in 2 points per forget, times 6 times forgetting gives 12. But since it is a deduction in points the final integer answer is -12

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3 years ago

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Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

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3 years ago

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Evaluate the response...

Kruka [31]

Answer:

um 18 lol

Step-by-step explanation:

Please mark brainliest

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3 years ago

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I’m not sure how to do this problem

strojnjashka [21]

The first one would be x^12

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3 years ago

What pattern do you notice in the numbers below? 1 = 1 × 1, and 1 × 1 × 1, and 1 × 1 × 1 64 = 8 × 8, and 4 × 4 × 4 729 = 27 × 27

11111nata11111 [884]

Answer:

<h3>C. They are both perfect squares and perfect cubes.</h3>

Step-by-step explanation:

Perfect squares are numbers that their square root can be found easily without any remainder.

Given the following patterns;

1*1 = 1 and 1*1*1 = 1

It can be seen that 1 is 1 perfect square since 1*1 = 1² = 1

Also 1 is perfect cube since 1*1*1 = 1³ = 1 (cube of the value gives 1)

Similarly for the expression;

8*8 = 64

8² = 64 (since the square of 8 gives 64, then 64 is known to be a perfect square)

Also 4*4*4 = 64

i.e 4³ = 64 (This shows that the cube root of 64 is 4 making it a perfect cube since we can get a whole number for the cube root of 64)

The same is applicable for other expressions 729 = 27 × 27, and 9 × 9 × 9, 4,096 = 64 × 64, and 16 × 16 × 16

This values are easily expressed as a constant multiple of a number showing that they are both perfect squares and perfect cubes.

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3 years ago