If n is the first integer, then n+2 is the second one. The equation for the sum can be written as
n + (n+2) = 24 . . . . . . this equation can be used to solve the problem
2n = 22 . . . . . . . . . . . simplify, subtract 2
n = 11
The integers are 11 and 13.
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I like to solve problems like this by looking at the average of the integers. Here, it is 24/2 = 12. The consecutive odd integers whose average is 12 are 11 and 13.
There are 10·9/2 = 45 ways to choose 2 winners from 10 entrants.
There are 5·4/2 = 10 ways to choose 2 winners from Pike.
The probability that both winners are from Pike is 10/45 = 2/9.
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There are n ways to choose the first winner from a pool of n. There are n-1 ways to choose the second one, hence n(n-1) ways to choose two from n when order matters. Since this counts the choices (1)(2) and (2)(1) as two different possibilities, we need to divide by 2 when order doesn't matter.
Answer:
x^2 - 6x + 9
Step-by-step explanation:
(x - 3)^2
(x - 3)(x - 3)
x^2 - 3x - 3x + 9
x^2 - 6x + 9
Hey there!
3^2 + 7 • 2
3^2 = 3 • 3 = 9
9 + 7 • 2
7 • 2 = 14
9 + 14 = 23
Answer: 23 ☑️
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
X=11.2
10. 14
—- = ———
8. X
10x= 112
————-
10. 10
X=11.2
