I assume you mean the equation
Since i = √(-1), we have i⁴ = 1 and so i⁵ = i. Then 2x + 3 must be some multiple of 5.
Now just check for which of the given choices that this holds:
x = 16 ⇒ 2x + 3 = 35 (yes)
x = 11 ⇒ 2x + 3 = 25 (yes)
x = 10 ⇒ 2x + 3 = 23 (no)
x = 14 ⇒ 2x + 3 = 31 (no)
Answer is B
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Answer:
what are we actually solving for?....
anyways I had a suggestion ion know if it's right or wrong....
<em>Isolate</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>by</em><em> </em><em>diving</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>don't</em><em> </em><em>contain</em><em> </em><em>the</em><em> </em><em>vari</em><em>able</em><em>.</em>
<em>Therefore</em><em> </em><em>x</em><em>=</em><em>7</em><em>.</em><em>2</em>
Ok, ranked by axis of symmetry
basically x=something is the axis of symmetry
the way to find the axis of symmetry is to convert to vertex form and find h and that's the axis of symmetry
but there's an easier way
for f(x)=ax^2+bx+c
the axis of symmetry is x=-b/2a
nice hack my teacher taught me
so
f(x)=3x^2+0x+0
axis of symmetry is -0/(3*2), so x=0 is the axis of symmetry for f(x)
g(x)=1x^2-4x+5,
axis of symmetry is -(-4)/(2*1)=4/2=2, x=2 is axis of symmetry for g(x)
h(x)=-2x^2+4x+1
axis of symmetry is -4/(2*-2)=-4/-4=1, x=1 is the axis of symmetry for h(x)
0<1<2
axisies
f(x)<h(x)<g(x)
order based on their axises of symmetry is f(x), h(x), g(x)
Answer:
I don't have a protractor with me but if you do look where x is and line the little hole on the bottom of the protractor on the crossing point and see what degree the angle is at. Hope I helped :)
Step-by-step explanation:
