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marysya [2.9K]
4 years ago
9

Is .158 more than .58

Mathematics
2 answers:
irina [24]4 years ago
8 0
No because 1 is smaller than 5
Aloiza [94]4 years ago
3 0
No, of course not! Remember that tenths are more than hundredths or thousandths, regardless of the value of the digit. .1 is more than .05, and even .0999999. In this, .58 is larger than .158.
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Find the points of intersection of the lines 10x−4y=2 and 2x+8y=7 without graphing.
Jet001 [13]

Answer:

x=\frac{1}{2},y=\frac{3}{4}

Step-by-step explanation:

Given:

10x-4y=2 ,2x+8y=7

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Solution:

In substitution method, the system of equations is solved by expressing one variable in terms of another, as a result, removing one variable from an equation.

10x-4y=2 \\2(5x-2y)=2\\5x-2y=1\\5x=1+2y\\x=\frac{1+2y}{5}

Put x=\frac{1+2y}{5} in the equation 2x+8y=7

2x+8y=7\\2[\frac{1+2y}{5}]+8y=7\\ 2+4y+40y=35\\44y=35-2\\44y=33\\y=\frac{33}{44}\\ =\frac{3}{4}

Put y=\frac{3}{4} in the equation x=\frac{1+2y}{5}

x=\frac{1+2y}{5}\\=\frac{1}{5}[1+2(\frac{3}{4})]\\=\frac{1}{5}[1+(\frac{3}{2})]\\\\=\frac{1}{5}(\frac{2+3}{2}) \\\\=\frac{1}{5}(\frac{5}{2})\\\\=\frac{1}{2}

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x=\frac{1}{2},y=\frac{3}{4}

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3 years ago
Which expression would be easier to substitute into the other​ equation, in order to solve this​ problem? Explain your reasoning
rosijanka [135]

Answer:

x=3y-2 substitute is easier to solve the equation

Step-by-step explanation:

given x=3y-2.............(1)

x+3y=4................(2)

put x=3y-2 in equation (2)

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+2

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y=1

x=3y-2

x=3(1)-2=1

x=3y-2 substitute is easier to solve the equation answer

7 0
3 years ago
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