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Agata [3.3K]
3 years ago
5

What expression is equivelent to 8-5(3x-7)

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

8 - 5(3x - 7)

8 - (5.3x - 5.7)

8 - (15x - 35)

8 - 15x + 35

43 - 15x

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How much does an ice cream cost with 11 ounces of toppings? If they charge $3.00 for an ice cream, plus 50 cents per ounce of to
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Answer:

$8.50

Step-by-step explanation:

multiply 0.50 by 11 to get 5.5 and then add the 3 dollars from the ice cream to get 8.5 - make sure to change 8.5 to $8.50

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The width of a vegetable garden is
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Answer: So, the length (L) = 7 3/4 ft = 31/4 (as an improper fraction)

 

the width (W)  = (1/3)xL

 

So the width = 1/3 x (31/4) =

31/12 = 2  7/12 feet

Step-by-step explanation:

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What is range of 34,56,13,98, and 75?<br><br> A) 23<br><br> B) 85 <br><br> C) 56 <br><br> D) 55.2
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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
masya89 [10]

a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

5 0
2 years ago
In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers
ElenaW [278]
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number":  "i" ;  which represents the "imaginary number" ;  " √-1 " .

Since:  "i = √-1" ; 

Note that:   " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
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