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olga55 [171]
3 years ago
10

Plss can someone help me out with thissss!!!!!!!!!!!

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
If there aren’t any degrees and it doesn’t state that the triangle is equilateral then you cannot solve this equation without more information
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A smaller circle passes through the center of, and is tangent to, a larger circle. The area of the smaller circle is 9 square un
Schach [20]

Answer:

Area of bigger circle = 36.32cm²

Step-by-step explanation:

Kindly find attached rough sketch for your reference

This problem bothers on the mensuration of flat shapes, a circle

Kindly find attached

Given data

Area of small circle =9cm³

Say we assume the all unit is in cm

From the diagram we can see that the diameter of the small circle is the radius of the bigger circle

So let us solve for the diameter of the small circle

9= πr²

r²=9/3.142

r²= 2.86

r=√2.86

r= 1.7cm

But diameter of small circle

d= 2r

d= 1.7*2= 3.4cm

Hence the radius of the bigger circle is 3.4cm

Area of bigger circle =πr²

=3.142*3.4²

=3.142*11.56

Area of bigger circle = 36.32cm²

7 0
4 years ago
The perimeter of the triangle is 34 cm. Solve for x.
Musya8 [376]
5x-2+x-3+x-3 = 34
7x-8 = 34
7x/7 = 42/7
x = 6
3 0
3 years ago
Read 2 more answers
Most flat screen TVs today are made with an aspect ratio (ratio of the length to the height) of 16:9. Xenock Electronics' top se
ycow [4]
What question is more than paragraph? Good luck buddy with that
8 0
4 years ago
How many pairs of whole numbers have a sum of 99
alexandr402 [8]

With the sum of 99, we will get 50 pairs whole numbers. Why?

Let’s start with

0+ 99

1 + 98

2 + 97

3 + 96

4 + 95

5 + 94

6 + 93

7 + 92

8 + 91

9 + 90

10 + 89

………

……..

43 + 49

44 + 50


Therefore, if you’re going to count all pairs of whole number, you will get 50 pairs of whole number with the sum of 99.

Hope this helps!

4 0
3 years ago
Read 2 more answers
What is the sum of -19 and the product of 48 ?
IceJOKER [234]
It has to be -912 because i checked on a caculator
5 0
3 years ago
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