Answer:
0.430625 = 0.431
Step-by-step explanation:
Let W represent winning, D represent a draw and L represent a loss.
12+ points can be garnered in each of the following ways.
6W 0D 0L
5W 1D 0L
5W 0D 1L
4W 2D 0L
4W 1D 1L
4W 0D 2L
3W 3D 0L
The probability of getting 12+ points is the sum of all these 7 probabilities.
Knowing that P(W) = 0.5
P(D) = 0.1
P(L) = 0.4
P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625
P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875
P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075
P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375
P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075
P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15
P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025
The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625
Answer:
Below
Step-by-step explanation:
● x-20 = y+20 (1)
● 2(y-22) = x+22 (2)
This is a system of simulataneous equations
Let's simplify the expressions first
● x -20 = y + 20 (1)
Add 20 to both sides
● x -20 + 20 = y+20 +20
● x = y + 40 (1)
● 2(y-22) = x+22 (2)
● 2y - 44 = x +22
Substrat 22 from both sides
● 2y-44-22 = x+22-22
● 2y -66 = x (2)
This is the new system:
● x = y+40 (1)
● x = 2y-66 (2)
Substract (2) from (1)
● x-x = y+40-(2y-66)
● y+40-2y+66 = 0
● -y +106 = 0
● y = 106
Replace y with 106 in (1)
● x = y +40
● x = 106+40
● x = 146
So the solutions are (146,106)
39 cents that would be the answer for your question hopefully
Answer:
-15 plus or minus the square root of 65 all over 4 (All over means fraction)
