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aleksandrvk [35]
2 years ago
14

What is the solution?

Mathematics
1 answer:
BaLLatris [955]2 years ago
4 0

Answer:

What's the question?

Step-by-step explanation:

I hope you have a good night btw!!!

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I need answer ASAP <br> No links please
dezoksy [38]

Answer:

Step-by-step explanation:

let l be length of string.

Then 70/l=sin 40

l=70/sin 40 ≈108.9 ft

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S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and
Anvisha [2.4K]

Answer :Answer: Did you get helped on this one?          

Step-by-step explanation: okay yup yup have a good day OKAY

Step-by-step explanation: HAVE A GOOD ONE OKAY

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Allisa [31]
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3 years ago
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Vera_Pavlovna [14]

Answer:

2

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3 0
3 years ago
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What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
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