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3 years ago

What is the solution?

Mathematics

1 answer:

BaLLatris [955]3 years ago

4 0

Answer:

What's the question?

Step-by-step explanation:

I hope you have a good night btw!!!

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dezoksy [38]

Answer:

Step-by-step explanation:

let l be length of string.

Then 70/l=sin 40

l=70/sin 40 ≈108.9 ft

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2 years ago

S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and

Anvisha [2.4K]

Answer :Answer: Did you get helped on this one?

Step-by-step explanation: okay yup yup have a good day OKAY

Step-by-step explanation: HAVE A GOOD ONE OKAY

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3 years ago

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Allisa [31]

2miles=20km
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Runned 0.5 miles in total

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3 years ago

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Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

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3 years ago