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spin [16.1K]
3 years ago
5

Scientists use restriction ________ to

Biology
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer: enzymes (B)

Explanation: just took the quiz on usa test prep!

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In a cross of two heterozygous parents, 25% of the offspring should have the recessive phenotype.
Degger [83]
True because if you were to do a punnet square, it would show 25% recessive 25% dominate and 75% hybrid 

7 0
4 years ago
snakes rely on behavioral homeostasis to get warmer. what might a snake do in order to increase its body temperature.
Shalnov [3]

Answer:

They bask in the sun

Explanation:

In other words, they lay on their back to raise their body temperature.

I hope this helps!

8 0
3 years ago
Read 2 more answers
When bone tissue first evolved in vertebrates, it was found within _____?
Sonbull [250]
Exoskeleton

Exoskeleton is a evolutionary innovation. This is operated by muscles attached to it and acts as an armor. Other than support this is an adaptive mechanism to provide protection against predators. In vertebrates, it is considered as the dermal bone that developed via membranous ossification. Fishes retained their exoskeleton in the form of their scales. However, in some organisms terrestrial evolution allows the loss of exoskeleton and formed a more mobile endoskeleton,
3 0
3 years ago
2
sergejj [24]

Answer:

There is no diagram but

It would be A if you were looking at the endoplasmic reticulum (ER).

It would be B if you were looking at a mitochondrion.

I do not remember what C is, so if it is not the ER, Golgi apparatus, or the mitochondrion, it is most likely C.

It would be D if you were looking at a Golgi apparatus

8 0
3 years ago
A fruit fly population has a gene with two alleles, A1 and A2. Tests show that 70% of the gametes produced in the population con
IceJOKER [234]

Answer:

Option C

Explanation:

Given ,

A1 allele is carried by 70 % people

Let us assume A1 s dominant genotype

This means p= \frac{70}{100} = 0.7

Thus, frequency of allele in the given population is 0.7

It is also given that the population is in Hardy-Weinberg equilibrium thus

p+q=1\\0.7+q=1\\q = 1-0.7\\q= 0.3

Frequency of fruit fly with genotype A2A2 will be

q^2\\= (0.3)^2\\= 0.09

As per Hardy-Weinberg's second equation of equilibrium

p^{2} + q^{2} + 2pq = 1\\0.49+0.09+2pq = 1\\2pq = 1-0.49-0.09\\2pq= 0.42

Hence, option C is correct

7 0
3 years ago
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