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sergij07 [2.7K]
2 years ago
10

A newspaper headline writer found that the more adjectives she put in the titles of her articles, the greater the number of news

papers that were sold that day. This relationship between numbers of adjectives and newspaper sales must be:
Business
1 answer:
Ivahew [28]2 years ago
6 0

Answer:

Positive.

Explanation:

A linear function has a positive relationship and as such an increase in one variable (input variable) causes an increase in the other variable (output variable) i.e the variables are directly proportional. Thus, the graph of a linear function is a straight-line and its slope is always constant.

On the other hand, nonlinear function has a negative relationship and as such an increase in one variable (input variable) causes a decrease in the other variable (output variable) i.e the variables are inversely proportional.

This ultimately implies that, the graph of a nonlinear function is a curved line and whose direction is constantly changing

In this scenario, the relationship between numbers of adjectives and newspaper sales must be positive because the higher the amount of adjectives put in the titles of her articles, the greater the number of newspapers that would be sold on a particular day.

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A country is currently producing bricks and spatulas using all of their resources and satisfying the wants of their economy. If
makkiz [27]

Answer:

C. The country will have a smaller marginal return from bricks.

Explanation:

This is because it will lead to an increased production in the economy and ppf will shift outward.

5 0
3 years ago
The market for carbon allowances
erik [133]
The market for carbon allowances is set by the regulatory authority.
3 0
3 years ago
Matt Company uses a standard cost system. Information for raw materials for Product RBI for the month of October follows: Standa
Troyanec [42]

Answer:

$100 favorable

Explanation:

The computation of the material purchase price variance is shown below:

= Actual Quantity purchased × (Standard Price - Actual Price)

= 2,000 pounds × ($1.60 - $1.55)

=  2,000 pounds × $0.05

= $100 favorable

Simply we took the difference between the standard and the actual price, and then multiply it by the actual quantity purchased

6 0
3 years ago
Equipment was acquired on January 1, 2021, for $33,000 with an estimated four-year life and $2,000 residual value. The company u
Lostsunrise [7]

Answer:

Gain= $850

Explanation:

Giving the following information:

Purchase price= $33,000

Useful life= 4 years

Residual value= $2,000

Sale= $10,600.

<u>First, we need to calculate the annual depreciation:</u>

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (33,000 - 2,000)/4= $7,750

<u>Now, we can calculate the accumulated depreciation:</u>

Accumulated depreciation= 7,750*3= $23,250

<u>To calculate the gain or loss, we need to use the following formula:</u>

Gain/loss= selling price - book value

Book value= purchase price - accumulated depreciation

Book value= 33,000 - 23,250= $9,750

Gain/loss= 10,600 - 9,750

Gain= $850

4 0
3 years ago
Your​ company, which has a MARR of​ 12%, is considering the following two investment​ alternatives:
mote1985 [20]

Answer:

future worth:

project A  11,615.26

project B  12,139.18‬

It should choose project B as their future value is greater

IRR of project A: 13.54%

We should remember that the IRR is the rate at which the net value is zero thus, equals the inflow with the cash outlay

It is calculate with excel or financial calculator due to the complex of the formula.

Explanation:

Project A

We calculate the future value of the cash flow per year and cost as we are asked for future value. The salvage value is already at the end of the project life so we don't adjust it.

Revenues future value

C \times \frac{(1+r)^{time} -1}{rate} = FV\\  

C 15,000

time 8

rate 0.12

15000 \times \frac{(1+0.12)^{8} -1}{0.12} = FV\\  

FV $184,495.3970  

Expenses future value

C \times \frac{(1+r)^{time} -1}{rate} = FV\\

C 3,000

time 10

rate 0.12

3000 \times \frac{(1+0.12)^{10} -1}{0.12} = FV\\  

FV $52,646.2052  

Cost future value

Principal \: (1+ r)^{time} = Amount  

Principal 40,000.00

time 10.00

rate 0.12000

40000 \: (1+ 0.12)^{10} = Amount  

Amount 124,233.93

Net future worth:

-124,233.93 cost - 52,646.21 expenses + 184,495.40 revenues + 4,000 salvage value

future worth 11,615.26

Project B

cost:

Principal \: (1+ r)^{time} = Amount  

Principal 60,000.00

time 10.00

rate 0.12000

60000 \: (1+ 0.12)^{10} = Amount  

Amount 186,350.89

expenses 52,646.21 (same as previous)

revenues

C \times \frac{(1+r)^{time} }{rate} = FV\\  

C 24,000

time 7

rate 0.12

24000 \times \frac{(1+0.12)^{7} -1}{0.12} = FV\\  

FV $242,136.2815  

TOTAL

242,136.28 + 9,000 - 52,646.21 - 186,350.89 = 12,139.18‬

Internal rate of return of project A

we write the time and cash flow for each period.

Time Cash flow

0 -40,000

1 -3,000

2 -3,000

3 12,000

4 12,000

5 12,000

6 12,000

7 12,000

8 12,000

9 12,000

10 16,000

IRR 13.54%

Then we write on excel the function =IRR(select the cashflow)

and we got the IRR of the project

6 0
3 years ago
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