Question

8x = 3" align="absmiddle" class="latex-formula">
solve by factoring please. I really need help I have no clue how to solve by factoring like I forgot the steps so can u work the steps out also please

Answer 1

Answer:

$x = 4 + \sqrt{19}$

Step-by-step explanation:

To solve by factoring, complete the square by dividing 8 from 8x in 2. Then square the result 4 to get 16. Add 16 to both sides.

$x^2 -8x = 3\\\\x^2 - 8x + 16 = 3 + 16\\\\(x-4)^2 = 19$

The equation is now factored. To solve, take the square root of both sides and solve for x.

$\sqrt{(x-4)^2} = \sqrt{19}\\\\x-4 = \sqrt{19} \\\\x = 4 + \sqrt{19}$