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3 years ago

Ben and his three friends were ordering pizza. They could spend at most $26. If a large

Mathematics

1 answer:

lutik1710 [3]3 years ago

6 0

Answer:

6 toppings

Step-by-step explanation:

The t in this equation represents the amount of toppings.

22 + 0.65t = 26

-22 -22

0.65t = 4

0.65t/0.65 = 4/0.65

t = 6

They could get 6 toppings and the total would be $25.90.

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Michael has a points card for a movie theater.

Vladimir [108]

Answer:

35+2.5v = 70

so the answer is 14

Step-by-step explanation:

i solved it xD

3 0

3 years ago

In fig. AB = AC, D is the midpoint of BC.<br><br> (i)Is  ADB ADC (ii) Is ∠B =∠C?

dexar [7]

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

$\triangle$ ADB $\cong\triangle$ ADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

3 0

3 years ago

Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

$x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18$

Factor the variable squared terms out of each binomial pairing:

$x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18$

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

$6+xyz+xyz+xyz=18$

Combine like terms:

$6+3xyz=18$

Subtract 6 on both sides:

$3xyz=12$

Divide both sides by 3:

$xyz=4$

4 0

3 years ago

Half the sum of 4 consecutive integers is 53 what are the integers?

Sphinxa [80]

Answer:

25,26,27, and 28

Step-by-step explanation:

Write consecutive integers as x,x+1,x+2,x+3,x+4, and so forth.

x+x+1+x+2+x+3

---------------------- = 53

1) Combine alike terms:

4x+6

------- = 53

2) Multiply both sides by 2:

4x+6=106

3) Subtract 6 from both sides:

4x=100

4) Divide both sides by 4:

x=25

5) Plug in 25 for x for all 4 integers:

6 0

3 years ago

The segments in each figure are tangent to the circle. Find each length.

zubka84 [21]

The tangents are equal length, so
.. 8x = x^2
We presume their length is not zero, so we can divide by x to get
.. 8 = 2x
.. 4 = x

Then the length of each tangent is 8*4 = 32 units.

3 0

4 years ago