Kevin would be 14 and Benjamin would be 10
For a survey like this, you want to take a random sample. It would be a good idea to use an alphabetical list of the students. Then, you could randomly select students from the list.
The principal would want to avoid surveying all the same type of students. For example, don't just ask the athletes.
Factorize the numerator and denominator, then simplify:
10/45 = (2×5)/(9×5) = 2/9
Now,
1/9 = 1/10 + 1/90
1/90 = 1/10 × 1/9 = 1/10 × (1/10 + 1/90) = 1/100 + 1/900
1/900 = 1/100 × 1/9 = 1/100 × (1/10 + 1/90) = 1/1000 + 1/9000
and so on, which is to say
1/9 = 1/10 + 1/100 + 1/1000 + …
or
1/9 = 0.111…
so that multiplying both sides by 2 gives
2/9 = 0.222…
Answer:
the answer is C: m<CDB=63
