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Masteriza [31]
2 years ago
5

5(-5x - 2) = 10(-5x+4)

Mathematics
2 answers:
natulia [17]2 years ago
7 0

Answer:

5(-5x - 2) =

-25x - 10

10(-5x+4) =

-50x + 40

-25x-10 = -50x+40

-25x = -50x + 50

25x = 50

x = 2

lions [1.4K]2 years ago
6 0

Answer: 1. 5(-5x-2)=-35

2. 10(-5x+4)= -10

So -35 = -10

It not Equal Together If it was equal together it going to be -35 = -35

Step-by-step explanation: is this how you want it explain and I hope I help

You might be interested in
A tea that is 22% jasmine is blended with a tea that is 13% jasmine. How many pounds of the 22% jasmine tea are used to make 10l
tatiyna

Given

A tea that is 22% jasmine is blended with a tea that is 13% jasmine

Find out the how  many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

To proof

Let us assume that the a tea that is 22% jasmine is blended = a

Let us assume that the a tea that is 13% jasmine is blended = b

Total amount of tea made = 10lb

the equation be

a + b = 10

as given

jasmine tea are used to make 10lb of tea that is 19.3% jasmine.

write 22%  in the decimal form

= \frac{22}{100}

= 0.22

write 13%  in the decimal form

=\frac{13}{100}

= 0.13

write 19.3%  in the decimal form

=\frac{19.3}{100}

= 0.193

than the equation be

0.22a + 0.13b = 0.193 × 10

on simplify

22a + 13b = 193

two equation becomes

22a + 13b = 193 and a + b = 10

multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193

we get

22a - 13a + 13b -13b = 193 - 130

9a = 63

a = 7lb

put this value in the a + b = 10

we get

7 + b = 10

b = 3lb

Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .

Hence proved


4 0
3 years ago
The radius of a semicircle is 9.1 centimeters. What is the semicircle's perimeter?
Sloan [31]

Answer:

<u>46.77 cm</u>

Step-by-step explanation:

Perimeter of the semicircle = Circumference + 2r

  • πr + 2r = r (π + 2)
  • 9.1 (3.14 + 2)
  • 9.1 (5.14)
  • <u>46.77 cm</u>
8 0
2 years ago
What value for C will make the expression a perfect square trinomial x2-7x+c
Tom [10]

Answer:

The value of c is 12.25

Step-by-step explanation:

we know that

A perfect square trinomial is of the form

(x-a)^{2}=x^{2}-2ax+a^{2}

In this problem we have

x^{2}-7x+c

so

equate the equations

x^{2}-7x+c=x^{2}-2ax+a^{2}

we have

the following equations

-7x=-2ax -----> equation A

and

c=a^{2} -----> equation B

<u>Solve the equation A</u>

-7x=-2ax

7=2a

a=3.5

<u>Solve the equation B</u>

c=a^{2}

c=3.5^{2}=12.25

therefore

(x-3.5)^{2}=x^{2}-7x+12.25

The value of c is 12.25

7 0
3 years ago
Read 2 more answers
i ran 3hrs and 2 mins to run 26 miles if i ran at the same rate for the whole race how many minutes did it take to run each mile
oksian1 [2.3K]
7 minutes per mile.
8.57 miles per hour
8 0
3 years ago
A student studying his classmates' cars' ages reports the 5-number summary as {1, 3, 4, 8, 20}. what is the iqr for his data?
timurjin [86]

IQR for the data {1, 3, 4, 8, 20} is 5.

Interquartile Range(IQR) for a data is defined as the difference between third quartile and first quartile.

denoted by  IQR=Q₃-Q₁              (Q₃ is third quartile and Q₁ is first quartile)

The five number summary of a data set is represented as

{minimum, first quartile , second quartile , third quartile , maximum}..…(1)

According to the question

{1, 3, 4, 8, 20}

On comparing it with equation   …(1)

minimum=1

Q₁ =3    , Q₂=4 , Q₃=8 , maximum =20

IQR=Q₃-Q₁

Substituting the values we get

IQR=8-3=5.

Therefore , Interquartile Range for the data {1, 3, 4, 8, 20} is 5.

Learn more about Inter Quartile Range here brainly.com/question/28037049

#SPJ4

3 0
1 year ago
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