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PIT_PIT [208]
2 years ago
9

Just look at the picture

Mathematics
1 answer:
qwelly [4]2 years ago
5 0

Answer:

What is the question??

Step-by-step explanation:

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For two events, M and N, P(M)=0.7, P(N|M)=0.3, and P(M'|N')
dexar [7]
Topic:C<span>onditional Probability

</span>For any two events A and B, where P(B) ≠ 0, P( A | B ) = P( A ∩ B ) / P( B ) = P( B | A) * P(A) / P(B)..i.e..{the probability of A given B is equal to the probability of A and B divided by the probability of B}

<span>For a set of events A1, A2, A3, ... , An,
</span>hence,
P(B) 
<span>= P(B and A1) + P(B and A2) + ... + P(B and An) </span>
= P(B | A1) * P(A1) + P(B | A2) * P(A2) + ... + P(B | An) * P(An)

P(M | N) 
<span>= P(N | M) * P(M) / P(N) </span>
<span>= P(N | M) * P(M) / (P(N | M) * P(M) + P(N | M') * (1 - P(M))) 
</span><span>Substitute Values.... you get ?

</span>
5 0
2 years ago
Step my step I don’t understand(:Brainliest
PSYCHO15rus [73]
Its the first one because if the circle is filled in than it is 2and more or the thing
3 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
Seclate all the numbers that are solutions to the inequalitt w&gt;1.
natima [27]

Answer:

The numbers should be A. 5 and C. 0.

Hope I Helped

6 0
2 years ago
Read 2 more answers
HELP!!Part B What is the approximate volume of each slice that Hattie's grandma cut? (arc length of each slice is 3 in, vol. of
GalinKa [24]

The approximate volume of each slice will be 63.5 inch². The total cake is divided into the four cylindrical slice.

<h3>What is volume?</h3>

It is defined as a three-dimensional space enclosed by an object or thing.

The volume of the slice is;

\rm V = \pi r^2 h\\\\\ \rm 81 \pi = \pi  \times (r)^2 \times 4 \\\\ r= 4.5 \ inch

If the grandma cut four pieces, is the approximate volume of each slice that Hattie's grandma cut will be;

The approximate volume of each slice will be;

\rm V = \PI r^2 h \\\\ \rm V = 3.14 \times (4.5)^2 \times 1 \\\\ V=63.5 \ inch^2

Hence, the approximate volume of each slice will be 63.5 inch².

Learn more about the volume here:

brainly.com/question/16788902

#SPJ2

6 0
2 years ago
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