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2 years ago

A Ferris wheel has a diameter of 90 feet. How far does car travel in one revolution in terms of π?

Mathematics

1 answer:

Yuri [45]2 years ago

6 0

90 $\pi$

one revolution is the circumference of the circle.

C= $\pi$ d=90 $\pi$

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Juan ordered 4 CDs for $48.96, which includes a $5.00 shipping charge. If each CD was the same price, what was the cost of each

Savatey [412]

Answer:

Each CD would be $10.99

Step-by-step explanation:

$48.96-5.00=43.96

43.96/4= 10.99

4 0

2 years ago

Read 2 more answers

8 t-shirts and a hat costs £42 3 t-shirts and a hat costs £17 how much does the hat and t shirt cost

cestrela7 [59]

17 + 5shirts = 42
5shirts = 42-17 = 25
1shirt = 25/5 = 5

A shirt costs £5.

3*5 + 1hat = 17
15 + 1hat = 17
1hat = 2

A hat costs £2

7 0

2 years ago

If r = 4 units and x = 13 units, then what is the volume of the cylinder

irina [24]

Im going to go with the volume being 653.45 because v = pie r squared h = pie times 4 squared times 13 which equals 653.45... hope its correct !

6 0

3 years ago

In a study of 250 adults, the mean heart rate was 70 beats per minute. Assume the population of heart rates is known to be appro

klasskru [66]

This is a good question!

The steps are like follows:

Form the confidence level (99%), we calculate the "alpha" value
alpha=1-(99/100)=0.01

Now, calculate the critical probability (p-start)
p*=1-(alpha/2)=1-(0.01/2)=0.995

z-score could be calculated from p*,,,
z-score=2.57583
(http://www.socscistatistics.com/tests/ztest/zscorecalculator.aspx)

Now, calculate the Margin of Error:
standard deviation = s
number of adults = n

ME=(z*s)/(sqrt n)=(2.57583*12)/(sqrt 250) = 1.955

The confidence interval = mean +or- ME
= 70+1.955 or 70-1.955

So that we can conclude that the 99% confidence interval for the mean beats per minute is 68.045 and 71.955

I hope you got the idea!

If you still need help, just let me know!

4 0

2 years ago

A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur

Vladimir79 [104]

Answer:

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The volume of the open-topped box is equal to

$V=LWH$

where

$L=(7-2x)\ in\\W=(2-2x)\ in\\H=x\ in$

substitute

$V=(7-2x)(2-2x)x$

Convert to expanded form

$V=(7-2x)(2-2x)x\\V=(14-14x-4x+4x^{2})x\\V=14x-14x^2-4x^2+4x^{3}\\V=4x^{3}-18x^{2} +14x$

using a graphing tool

Graph the cubic equation

Remember that

The domain for x is the interval -----> (0,1)

Because

If x>1

then

the width is negative (W=2-2x)

The maximum is the point (0.46,3.02)

see the attached figure

therefore

The value of x that maximizes the volume enclosed by this box is 0.46 inches

The maximum volume is 3.02 cubic inches

8 0

2 years ago