All categories

2 years ago

A density graph for all of the possible times from 50 seconds to 300 seconds

Mathematics

1 answer:

vazorg [7]2 years ago

8 0

Answer: D. The probability of a time from 75 seconds to 250 seconds.

Step-by-step explanation:

We know that a density curve graph for all of the possible values from a to b can be used to find the the probability of the values from a to b .

Given: A density graph for all of the possible times from 50 seconds to 300 seconds.

Then it can be used to find the the probability of a time in the range from 50 seconds to 300 seconds.

From all the given option only option D gives the interval which is lies in the above range.

i.e A density graph for all of the possible times from 50 seconds to 300 seconds can be used to determine the probability of a time from 75 seconds to 250 seconds.

You might be interested in

What is the slope of the line represented by the equation y = -1/2x +1/4?

ELEN [110]

Answer:

-1/2

Step-by-step explanation:

y = -1/2x + 1/4 is in slope y-intercept form : y = mx + b

m is slope

Slope = -1/2

4 0

3 years ago

What is an equation for this relationship? The table shows the total number of squares in each figure below. Picture attached

olasank [31]

If you substitute the values for x and y you will find that D. is the only function which satisfies the given values.

5 0

3 years ago

Record the results of the class demonstrations and discussions in your notes.

lana [24]

You shoulda just paid attention to class my guy, nobody can answer this.

7 0

3 years ago

Among 8 PS4s, four are good and four have defects. Unaware of this, a customer buys 5 PS4s.

astraxan [27]

Answer:

(a) The probability of exactly 2 defective PS4s among them is 0.3125.

(b) The probability that exactly 2 are defective given that at least 2 purchased PS4s are defective is 0.3846.

Step-by-step explanation:

Let X = number of defective PS4s.

It is provided that 4 PS4s of 8 are defective.

The probability of selecting a defective PS4 is:

$P(X)=p=\frac{4}{8}=0.50$

A customer bought n = 5 PS4s.

The random variable X follows a Binomial distribution with parameters n = 5 and p = 0.50.

The probability function of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, 3...$

(a)

Compute the probability of exactly 2 defective PS4s among them as follows:

$P(X=2)={5\choose 2}(0.50)^{2}(1-0.50)^{5-2}=10\times0.25\times0.125=0.3125$

Thus, the probability of exactly 2 defective PS4s among them is 0.3125.

(b)

Compute the probability that exactly 2 are defective given that at least 2 purchased PS4s are defective as follows:

$P(X=2|X\geq 2)=\frac{P(X=2\cap X\geq2)}{P(X\geq2)} =\frac{P(X=2)}{P(X\geq 2)}$

The value of P (X = 2) is 0.3125.

The value of P (X ≥ 2) is:

$P(X\geq 2)=1-P(X$

Then the value of P (X = 2 | X ≥ 2) is:

$P(X=2|X\geq 2)=\frac{P(X=2)}{P(X\geq 2)}=\frac{0.3125}{0.8125} =0.3846$

Thus, the probability that exactly 2 are defective given that at least 2 purchased PS4s are defective is 0.3846.

6 0

3 years ago

Read 2 more answers

What is the answer for 0.3(3-0.5)

charle [14.2K]

My answer for you was 0.75 because i calculated

4 0

3 years ago