The graph seems to show the solution to be the point (50, 11), and, indeed, that point checks in both equations!
To use algebra to solve the linear system, make the problem easier to solve by eliminating fractions.
Multiply all terms in the first equation by 40 (the denominator in the coefficient of q):

Multiply all terms in the second equation by 50:

Add the two resulting equations.

Plug that back into either equation to get q=50.
Answer:
90
Step-by-step explanation:
The first term = 6* 2^0 = 6
The second term = 6 * 2^ (2-1) = 6*2 = 12
The third term = 6* 2^(3-1) = 6*2^2 = 6*4 = 24
The fourth term = 6* 2^(4-1) = 6* 2^3 = 6*8 = 48
S4 is the sum of the 1st four terms
S4 = 6+ 12+24+ 48 = 90
Answer:
m∠BXC = 70°.
We start out with m∠XBC. It is 55°, because it is a corresponding angle with ∠AXY.
Since ∠XBC and ∠XCB are the base angles of an isosceles triangle, they are congruent. This means that m∠XCB = 55°.
To find the measure of ∠BXC, we find the sum of the two base angles in the isosceles triangle and subtract it from 180:
180-(55+55) = 180-110 = 70°
Step-by-step explanation: