Answer:
z - 2*x - 1.5*y = 0 maximize
subject to:
3*x + 5*y ≤ 800
8*x + 3*y ≤ 1200
x, y > 0
Step-by-step explanation:
Formulation:
Kane Manufacturing produce x units of model A (fireplace grates)
and y units of model B
quantity Iron cast lbs labor (min) Profit $
Model A x 3 8 2
Model B y 5 3 1.50
We have 800 lbs of iron cast and 1200 min of labor available
We need to find out how many units x and units y per day to maximiza profit
First constraint Iron cast lbs 800 lbs
3*x + 5*y ≤ 800 3*x + 5*y + s₁ = 800
Second constraint labor 1200 min available
8*x + 3*y ≤ 1200 8*x + 3*y + s₂ = 1200
Objective function
z = 2*x + 1.5*y to maximize z - 2*x - 1.5*y = 0
x > 0 y > 0
The first table is ( to apply simplex method )
z x y s₁ s₂ Cte
1 -2 -1.5 0 0 0
0 3 5 1 0 800
0 8 3 0 1 1200
Answer:
8
Step-by-step explanation:
3 + 4 = 7
6/12 + 1/2 = 1
7+1 = 8
Step-by-step explanation:
step 1. what is the question? solve for x? okay.
step 2. 28/54 = (2x+ 8)/(5x - 4)
step 3. 28(5x - 4) = 54(2x + 8) (cross multiplication)
step 4. 14(5x - 4) = 27(2x + 8) (divide both sides by 2)
step 5. 70x - 56 = 54x + 216 (distributive property)
step 6. 16x = 272 (group x's and add 56 to both sides)
step 7. x = 17 (divide both sides by 16).
Answer:
39 touchdowns and 13 fieldgoals
Step-by-step explanation:
Let t= touchdowns
f = fieldgoals
They scored 35 times
t+f = 35
Touchdown is 7 pts and fieldgoal is 3 pt
7t+3f = 193
Multiply the first equation by-7
-7t -7f =-245
Add this to the second equation
-7t -7f =-245
7t+3f = 193
----------------------
-4f =-52
Divide by -4
-4f/-4 = -52/-4
f = 13
Now we can find t
t+f = 35
t+13 = 52
Subtract 13 from each side
t+13-13 =52-13
t =39
