I believe the answer is 40%
Not entirely sure, hope I helped though!
For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
Answer:
The demabd function is:

Step-by-step explanation:
The demand follow the linear equation 
1. When p=$2.00 and q=9000, the equation is:

2. Whe p=$4.00 and q=0, the equation is:

3. Solve equation (1) for b:

4. Replace the value of b in equation (2)

The value of m is 4500
5. Calculate b, replacing m:

The value of b is 18000
Each gets one and a half. :-)
I hope I helped! :-)