Question

The table below shows some inputs and outputs of the invertible function f etc ​

Answer 1

Answer:

$(a)\ f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)=0$

Step-by-step explanation:

Given

The attached table

$(a)\ f^{-1}(-15)$

This represents an inverse function.

So, we look into x row for its value.

i.e.

$f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)$

Just like (a)

$f^{-1}(4) = -11$ ---- by looking into the x rows

$f(9) = 11$

So:

$f^{-1}(4) + f(9)=-11 + 11$

$f^{-1}(4) + f(9)=0$