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balu736 [363]
3 years ago
15

The table below shows some inputs and outputs of the invertible function f etc ​

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

(a)\ f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)=0

Step-by-step explanation:

Given

The attached table

(a)\ f^{-1}(-15)

This represents an inverse function.

So, we look into x row for its value.

i.e.

f^{-1}(-15) = -6

(b)\ f^{-1}(4) + f(9)

Just like (a)

f^{-1}(4) = -11 ---- by looking into the x rows

f(9) = 11

So:

f^{-1}(4) + f(9)=-11 + 11

f^{-1}(4) + f(9)=0

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Answer:

(a) \frac{-1i}{2}-1[/tex]

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(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

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After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

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5 0
4 years ago
4(-8x + 5) – (-33x – 26) ​
Keith_Richards [23]

Answer:

1x+46 is the answer

Step-by-step explanation:

=4(-8x + 5) – (-33x – 26)

opening brackets to simplify

=-32x+20+33x+26

=-32x+33x+20+26

=1x+46 is the answer

hope it will help :)

5 0
3 years ago
Read 2 more answers
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