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Goryan [66]
2 years ago
14

Which expression is equivalent to ( 4 1/3)^3 ?

Mathematics
1 answer:
shutvik [7]2 years ago
5 0
(13/3)^3 or (13/3)•(13/3)•(13/3)
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Will mark brainliest!! Please help asap!!
Anna007 [38]

Answer:

the answer is A

Step-by-step explanation:

8 0
3 years ago
Round to the nearest whole.<br> 782.36
ratelena [41]
The answer would be 782 because you would round down.
6 0
3 years ago
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How many solutions exist for 2|x − 1| = 8?
lora16 [44]
Two solutions exist,
2(x - 1) = 8
2x - 2 = 8
2x = 10
x = 5
&
2(x + 1) = 8
2x + 2 = 8
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4 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
I need help with this please!!!!
Lisa [10]

Answer:

∠3=95°

∠4=85°

Step-by-step explanation:

6 0
2 years ago
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