Question

HELP ASAP//BRAINLEST+THANKS: Subj:gravity formula stuff

Answer 1

Answer:

6.46

Step-by-step explanation:

h(t) = (1/2)$att^{2}$ + v0t + h0

Origin is at surface of water (h = 0), up is positive.

a = -g = -9.8 m/$s^{2}$

v0 = 25 m/s

h0 = 50 m

h(t) = -4.9t2 + 25t + 50

Find t when

7 = $-4.9t^{2}$ + 25t + 50

$4.9t^{2}$ - 25t - 43 = 0

t = [1/(2*4.9)] [25 ±√($25^{2}$ + 4*4.9*43)]

t = (0.102)(25 ± 38.312)

t > 0 ⇒ use only the positive square root

t = (0.102)(25 + 38.312) ≅ 6.46 s

It is 7m above the water at about 6.46 s