Answer:
![\left[\begin{array}{ccccc}&DF&SS&MS&F\\Regression&1&7200&7200&72\\Error&18&1800&100\\total&19&900\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D%26DF%26SS%26MS%26F%5C%5CRegression%261%267200%267200%2672%5C%5CError%2618%261800%26100%5C%5Ctotal%2619%26900%5Cend%7Barray%7D%5Cright%5D)
Explanation:
Sample size, n=20
Degrees of freedom is 1
Number of degrees of freedom for error is n-2 hence 20-2=18
Total number of degrees of freedom is 18+1=19
Standard error estimate is
Here,
Coefficient of determination
Here,
The total sum of squares is
SS total=SSR+SSE=7200+1800=9000
MSR=SSR=7200
F value is given by
The ANOVA table is then
True
(I’m not sure if that’s right a picture below may help with the answer too)
Answer:
Calculate the individual residential lifetime cancer risk.
Risk = Potential factor x CDI …… (1)
Calculate the value of C
C = 
t = d / v
t = 150 miles / 2 mile per hrs.
t = 75 hrs
t = 75/24
t = 3.13 days
Substitute the obtained value in (2).
C = 
C = 0.72 x e^(-0.1*3.13)
C = 0.72 x 0.7313
C = 0.526 mg/L
Substitute the obtained value in (1).
Risk = Potential factor x CDI
Risk = 0.30kg.d/mg x 0.526mg/L x 2L/d x 350day/365days
Risk = 0.3026
option 2 is your answer... thanks .. hope it helps
Answer:
we need to see what you're being asked about
Explanation: