Answer:
The answer is below
Explanation:
The practical considerations you might encounter when you increase the moment of inertia (I) while keeping the cross-sectional area fixed are:
1. Shapes of moment of inertia: Engineers should consider or know the different shapes of moment of inertia for different shape
2. Understanding the orientation of the beam: this will allow engineers to either increase or decrease the moment of inertia of a beam without increasing its cross sectional area.
Answer:
(a) 2.5 ksi
(b) 0.1075 in
Explanation:
(a)

Making
the subject then

where
is the stress and
is the strain
Since strain is given as 0.025% of the length then strain is 
Now substituting E for
then

(b)
Stress,
making A the subject then


where d is the diameter and subscripts o and i denote outer and inner respectively.
We know that
where t is thickness
Now substituting



But the outer diameter is given as 2 in hence



As already mentioned, 

Answer:
Teller, Loan Officer, and Tax Preparer
Explanation:
Answer:
Have the power company install insulated sleeves (also known as “eels”) over power lines.
Wearing PPE is the only way to prevent being electrocuted
Explanation:
To prevent electrocution at workplace, employers can ensure that the power company install insulated sleeves (also known as “eels”) over power lines. Additionally, the employees should wear PPEs which are insulators to prevent electrocution.
Answer:
0.304 L of Freon is needed
Explanation:
Q = mCT
Q is quantity of energy that must be removed = 47 BTU = 47×1055.06 = 49587.82 J
C is specific heat of Freon = 74 J/mol.K = 74 J/mol.K × 1 mol/120 g = 0.617 J/g.K
T is temperature in the area of Mars = 189 K
m = Q/CT = 49587.82/(0.617×189) = 452.23 g = 452.24/1000 = 0.45223 kg
Density of Freon = specific gravity of Freon × density of water = 1.49 × 1000 kg/m^3 = 1490 kg/m^3
Volume of Freon = mass/density = 0.45223/1490 = 0.000304 m^3 = 0.000304×1000 = 0.304 L