Calculate the areas under the stress-strain curve (toughness) for the materials shown in Fig. below, (a) plot them as a

defon

Answer:

Explanation:

Wow

5 0

3 years ago

Could a volcanic eruption suddenly bury a city and its inhabitants? (Plz explain to me)

andrezito [222]

Yes a volcanic eruption can suddenly bury a city ! if you look up some stuff on pompeii you can learn more

7 0

3 years ago

An AC power generator produces 50 A (rms) at 3600 V. The voltage is stepped up to 100 000 V by an ideal transformer and the ener

RSB [31]

Given:

$I_{rms} = 50 A$

voltage, V = 3600V

step-up voltage, V' = 100000 V

Resistance of line, $R = 100\ohm$

Solution:

To calculate % heat loss in long distance power line:

Power produced by AC generator, P = $50\times 3600$ W

P = 180000 W = 180 kW

At step-up voltage, V = 100000V or 100 kV

current, I = $\frac{P}{V'}$

I = $\frac{1800000}{100000}$

I = 1.8 A

Power line voltage drop is given by:

$V_{drop} = I\times R$

$V_{drop} = 1.8\times 100$

$V_{drop} = 180 V$

Power dissipated in long transmission line $P_{dissipated} = V_{drop}\times I$

Power dissipated in long transmission line $P_{dissipated} = 180\times 1.8$ = 324 W

% Heat loss in power line, $P_{loss} = \frac{P_{dissipated}}{P}\times 100$

% Heat loss in power line, $P_{loss} = \frac{324}{180000}\times 100$

$P_{loss} = 0.18%$

5 0

3 years ago

Under the right conditions, it is possible, due to surface tension, to have metal objects float on water. Consider placing a sho

stiv31 [10]

Answer:

D = 0.060732 in

Explanation:

given data

sp. wt. = 500 lb/ft³

diameter = 0.036 in

solution

we get here maximum diameter of rod that is express as

D = $\sqrt{\frac{8 \sigma }{\pi y}}$ ......................1

here $\sigma$ surface tension of water at 60⁰f = 5.03 × $10^{-3}$ lb/ft and y = 500 lb/ft³

so put here value and we will get

D = $\sqrt{\frac{8 \times 5.03 \times 10^{-3} }{\pi \times 500}}$

D = 0.005061 ft

D = 0.060732 in

4 0

3 years ago

A fuel gas containing 45.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00 degree C, and th

Dennis_Churaev [7]

Answer:

A)

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate - Q ( KJ )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

since combustion takes place in a constant-volume batch reactor

7 0

3 years ago