The tank shown in the accompanying figure is being filled by pipes 1 and 2. If the water level is to remain constant, what is th
e volumetric flow rate of water leaving the tank at 3? What is the average velocity of the water leaving the tank?
1 answer:
Answer: 2.93 ft/sec
Explanation: Calculate the volume/sec entering from the two inlets (Pipes 1 and 2), add them, and then calculate the flow in Pipe 3.
The table illustrates the approach. I calculated the volume of each pipe for a 1 foot section with the indicated diameters, divided by 2 for the radius of each using V = πr²h. Units of V are in^3/foot length. Now we can multiply that volume by the flow rate, in ft/sec, to obtain the flow rate in in^3/sec.
Add the two rates from Pipes 1 and 2 (62.14 in^3/sec) to arrive at the flow rate for Pipe 3 necessary to keep the water level constant. Calculate the volume of 1 foot of Pipe 3 (21.21 in^3/foot) and then divide this into the inflow sum of 62.14 in^3/sec to find the flow rate of Pipe 3 (in feet/sec) necessary to keep the water level constant.
That is 2.93 ft/sec.
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a) 23.89 < -25.84 Ω
b) 31.38 < 25.84 A
c) 0.9323 leading
Explanation:
A) Calculate the load Impedance
current on load side = 0.75 p.u
power factor angle = 25.84
= 0.75 < 25.84°
attached below is the remaining part of the solution
<u>B) Find the input current on the primary side in real units </u>
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<u>C) find the input power factor </u>
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<em>attached below is the detailed solution </em>
