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kicyunya [14]
3 years ago
15

Hii! please help asap. i’ll give brainliest

Mathematics
1 answer:
LiRa [457]3 years ago
3 0

Answer:

It's the last option

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I'm attaching the solutions.. please let me know if you have any questions.

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8 0
3 years ago
PLS HELP ME!!!! ASAP I WILL MARK BRAINLIEST!!!!!!
julsineya [31]

Answer:

(-3)^3 x^5

Step-by-step explanation:

x*x*x*x*x *(-3)*(-3)*(-3)

There are 5 x terms

x^5

There are 3 (-3) terms

(-3)^3

Multiply theses together

(-3)^3 x^5

8 0
3 years ago
Read 2 more answers
Simon is doing a card trick using a standard 52 card deck. He shows his friend a card, replace it, and then shows his other frie
Elza [17]
It would be 39/50 then 13/50 sry I didn't have time to simplify it.

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5 0
3 years ago
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
3 years ago
√3×sinx+cosx=0 tmf nghiệm
Crazy boy [7]

Answer:

x= -30

Step-by-step explanation:

√3×sinx+cosx=0

√3sinx=-cosx

√3sinx/-cosx=1

-sinx/cosx=1/√3

-tanx=1/√3

(tan(180-30))=1/√3

tan(-30)=1/√3

Therefore, x= -30

7 0
2 years ago
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