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DaniilM [7]
3 years ago
11

If an angle does not have a measure of 88°, then the angle is not an acute angle.

Mathematics
1 answer:
9966 [12]3 years ago
4 0
Any angle that opens up less than 90 degrees and it’s greater than 0 is acute
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Why does dividing by 100 shift each digit two places to the right?
alekssr [168]
The answer is D. If you divide 1000 by 100, it is 10. 10 is equal to 1/100 of its previous value of 1000.
3 0
3 years ago
PLEASE HELP ME ASAP!
AleksandrR [38]

Ok so first we find the equation that equals one variable.


2y = -x + 9

3x - 6y = -15


We solve for y.


2y = -x + 9

y = -x/2 + 9/2


Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


3x - 6y = -15

3(-x + 9/2) - 6y = -15

-3x + 27/2 - 6y = -15

-9y + 27/2 = -15

-9y = 3/2

-y = 3/18

y = -3/18


Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


y = -x/2 + 9/2

-3/18 = -x/2 + 9/2

-84/18 = -x/2

-x = 9 1/3

x = -28/3


Your answer would be (-28/3, -3/18)


Hope this helps!

6 0
3 years ago
Read 2 more answers
A football team lost 5 yards on each of 3 plays. Explain how you could use a number line to find the team's change in field posi
taurus [48]

Answer:

Step-by-step explanation:

5- 10- 15-

3 0
3 years ago
Previously, an organization reported that teenagers spent 24.5 hours per week, on average, on the phone. The organization thinks
Lena [83]

Answer:

We need to develop a one-tail t-student test ( test to the right )

We reject H₀  we find evidence that student spent more than 24,5 hours on the phone

Step-by-step explanation:

Sample size  n = 15     n < 30

And we were asked if the mean is higher than, therefore is a one-tail t-student test ( test to the right )

Population mean   μ₀  = 24,5

Sample mean   μ  =  25,7

Sample standard deviation s = 2

Hypothesis Test:

Null Hypothesis      H₀                             μ  =  μ₀

Alternative Hypothesis     Hₐ                  μ  >  μ₀

t (c) =  ?

We will define CI = 95 %  then   α = 5 %   α = 0,05    α/2 =  0,025

n = 15     then degree of freedom    df = 14

From t-student table  we get:  t(c) = 2,1448

And  t(s)

t(s) = ( μ  -  μ₀  ) / s/√n

t(s) = (25,7 - 24,5) /2/√15

t(s) = 2,3237

Now we compare   t(c)   and  t(s)

t(c)  =  2,1448         t(s)  = 2,3237

t(s) > t(c)

Then we are in the rejection region we reject H₀   we have evidence at 95% of CI that students spend more than 24,5 hours per week on the phone

8 0
2 years ago
Simplify the following polynomial and write the answer in standard form. (9-2x^3+5^2-4x+5) - (-2x^3+2x-3)
pogonyaev
If I am reading the question correctly it would come out to -6x+42  First do all the addition and squaring, then factor in that negative.  You come out to -2x^3 +2x^3-4x-2x+25+5+9+3.  The x^3's cancel, the -x's add to -6x, then all that other adds to 42.
7 0
3 years ago
Read 2 more answers
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