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2 years ago

Over the course of a weekend, the temperature drops 14.2 degrees on Friday, rises 13 degrees on Saturday, and drops another 10.8

degrees on Sunday. What is the overall change in temperature for the weekend?

Mathematics

1 answer:

Vladimir79 [104]2 years ago

5 0

$\bf \begin{array}{llrll}
friday&\downarrow &-14.20\\
saturday&\uparrow &+13.00\\
sunday&\downarrow &-10.80\\
&&\text{\textemdash\textemdash\textemdash}\\
&\Downarrow&-12.00
\end{array}$

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Hi there! please please help:)) have a good day

Elina [12.6K]

Answer:

Step-by-step explanation:

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2 years ago

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What is the area of this question.

frez [133]

The area of a circle is \pi r^2, where r is the radius of the circle. The diameter of a circle is the length of a line that passes through the center of the circle and stops at the perimeter of circle. The radius of a circle is half the diameter. Divide the diameter by 2 to find the radius.
1. 2.8 m / 2 = 1.4 m
2 . $\pi (1.2m)^2$ : Plug in the value we just found for r.
3. $\pi 1.44m^2$ : Use the order of operations (PEMDAS).
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2 years ago

Pasta Place needs to make pasta with garlic cream sauce for 80 guests at a party. One batch of pasta calls for 3 cups of cream a

uysha [10]

Answer:

Total pints of cream will they need for the pasta = 7 pints

Step-by-step explanation:

Given - Pasta Place needs to make pasta with garlic cream sauce for 80 guests at a party. One batch of pasta calls for 3 cups of cream and feeds 10 people. The restaurant already has 5 pints of cream in the fridge.

To find - How many more pints of cream will they need for the pasta?

Solution -

10 people = 3 cups of cream

⇒80 people = 8×3 = 24 cups of cream

Now,

We know that,

1 cup = 0.5 pints

⇒24 cup = 24×0.5 = 12 pints.

Now,

Given that, The restaurant already has 5 pints of cream in the fridge.

So,

Total pints more needed = 12 - 5 = 7 pints.

∴ we get

Total pints of cream will they need for the pasta = 7 pints

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2 years ago

Find the value of questions

Zolol [24]

Answer:

The simplified expression is:

$\frac{3^9y}{2\times \:81}=\frac{243y}{2}$

Step-by-step explanation:

Given the expression

$\frac{3^9\times \:y}{2\times 81}$

solving the expression

$\frac{3^9\times \:y}{2\times 81}=\frac{3^9y}{162}$

$=\frac{3^9y}{3^4\times \:2}$ ∵ $162=3^4\times \:2$

$=\frac{3^5y}{2}$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$=\frac{243y}{2}$ ∵ $3^5=243$

Therefore, the simplified expression is:

$\frac{3^9y}{2\times \:81}=\frac{243y}{2}$

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2 years ago

A 95-foot wire attached from the top of a cell phone tower makes a 62 degree angle with the ground. Joey is standing 150 feet be

a_sh-v [17]

Answer:

23.32 degrees

Step-by-step explanation:

We set up a large right triangle that has 2 triangles within it. The large triangle is a right triangle. The height of it is the height of the tower, the base angle is 62, the hypotenuse is 95, and the base measure is y. The other triangle has the same height which is the height of the tower, the angle is what we are looking for, and the base measure is 150 feet beyond y, so its measure is y + 150. We have enough information to find the height of the tower, so let's do that first. Going back to the first smaller triangle.

$sin62=\frac{x}{95}$ so the height of the tower is 83.88 feet. Now we need to solve for y. Using that same triangle and the tangent ratio, we find that $tan62=\frac{83.88}{y}$ . Now let's do the same thing for the other triangle with the unknown angle.

$tan\beta =\frac{83.88}{y+150}$

Solve both of these for y. The first one solved for y:

$y=\frac{83.88}{tan62}$

The second one solved for y will simplify to:

$y=\frac{83.88-150tan\beta }{tan\beta }$

Now that these are both solved for y, and y = y, we can set them equal to each other by the transitive property of equality:

$\frac{83.88-150tan\beta }{tan\beta }=\frac{83.88}{tan62}$

Cross multiply to get this big long messy looking thing:

$tan62(83.88-150tan\beta )=83.88tan\beta$

Distribute through the parenthesis to get

$83.88tan62-[(tan62)(150tan\beta)]=83.88tan\beta$

Get the unknown angles on the same side so it can be factored out:

$83.88tan62=83.88tan\beta +[(tan62)(150tan\beta )]$

And then factoring it out gives you:

$83.88tan62=tan\beta(83.88+150tan62)$

Divide to get

$tan\beta =\frac{83.88tan62}{83.88+150tan62}$

Do this on your calculator in degree mode to give you an angle measure of 23.32°. I know this is really hard to follow without being able to draw the pics for you like I do in my classroom, but hopefully you can follow my description and draw your own triangles and follow from that!

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2 years ago