Factor the denominator:
(3x-1)(x+2)
every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.
since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.
the answer here is C.
Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
Answer:
I think its 8a because in a regular octagon we have 8 sides.
The number -33 divisors are:
D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}
a × b = -33
<u>1) -33 × 1 = -33 ⇒ Sum is: -33 + 1 = -32</u>
2) -11 × 3 = -33 ⇒ Sum is: -11 + 3 = -8
3) -3 × 11 = -33 ⇒ Sum is: -3 + 11 = 8
4) -1 × 33 = -33 ⇒ Sum is: -1 + 33 = 32
<u>5) 1 × (-33) = -33 ⇒ Sum is: 1 + (-33) = 1 - 33 = -32</u>
6) 3 × (-11) = -33 ⇒ Sum is: 3 + (-11) = 3 - 11 = -8
7) 11 × (-3) = -33 ⇒ Sum is: 11 + (-3) = 11 - 3 = 8
8) 33 × (-1) = -33 ⇒ Sum is: 33 + (-1) = 33 - 1 = 32
<h2>The least possible sum of a and b is -32</h2>
to 1) and to 5)
Answer:
The ball will hit the ground at 10 seconds and its maximum height is 1024 feet.
Step-by-step explanation:
Height of a mountain, h = 90 feet
Upward velocity of a ball, u = 64 ft/s
Its height as a function of time can be written by using the second equation of motion as follows :
.....(1)
When it will hit the ground, f(x) = 0
It is quadratic equation.
t = -6 s and t = 10 s
Neglecting -6 seconds, the ball will hit the ground at 10 seconds.
For maximum height,
Put f'(x) = 0
Put t = 2 in equation (1)
Hence, the ball will hit the ground at 10 seconds and its maximum height is 1024 feet.
