All categories

3 years ago

Please answer the following question:

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

3 0

Answer:

99 cm²

Step-by-step explanation:

1/2 BH

1/2 18 x 11

9 x 11

You might be interested in

A decorator has just painted 400 tiles blue and green at a ratio of 5:20.how many were painted green ? how many were painted blu

zheka24 [161]

Blue tiles are 80.
Green tiles are 320

8 0

3 years ago

Calculate the average rate of change for the function

mezya [45]

$slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2(x-2)^2+1\qquad \begin{cases} x_1=-2\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(-2)}{4-(-2)} \\\\\\ \cfrac{[2(4-2)^2+1]~~ - ~~[2(-2-2)^2+1]}{4+2}\implies \cfrac{[9]~~ - ~~[33]}{6}\implies \cfrac{-24}{6}\implies -4$

7 0

2 years ago

In the geometric progression 1, 2, 4… what term is 512?

Levart [38]

The next term is double the previous term, so that the $n$ -th term is given recursively by

$\begin{cases}a_1=1\\a_n=2a_{n-1}&\text{for }n>1\end{cases}$

This rule tells us that

$a_2=2a_1$

$a_3=2a_2=2^2a_1$

$a_4=2a_3=2^3a_1$

and so on, with the explicit rule

$a_n=2^{n-1}a_1=2^{n-1}$

for $n\ge1$ .

If 512 is the $k$ -th term in the sequence, then

$512=2^{k-1}\implies\log_2512=\log_22^9=\log_22^{k-1}\implies9=k-1\implies k=10$

8 0

3 years ago

What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i

Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

Step-by-step explanation:

The question is incomplete:

What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions?

We can model this as a binomial random variable, with p=0.57 and n=14.

$P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}$

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

$P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\$

$P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\$

$P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\$

$P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886$

7 0

3 years ago

G=ta−F3 haha its shows GTA

kogti [31]

Hahaha but wait hold up is this an actual question?

3 0

3 years ago

Read 2 more answers