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3 years ago

What is the mode of the following numbers? 8,1,2,6, 1,4

Mathematics

2 answers:

ra1l [238]3 years ago

4 0

The mode is 1
This is because its the number that appears the most. Hope this helps

tatiyna3 years ago

3 0

Answer:

Step-by-step explanation:

Because, The mode is the value that appears most often in a set of data values. If X is a discrete random variable, the mode is the value x at which the probability mass function takes its maximum value. In other words, it is the value that is most likely to be sampled.

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What is the gcf of 39 and 42

natulia [17]

The answer is 3 because it goes into 39 and 42 and 6 doesn't go into 39

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4 years ago

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Ava has $110 in her piggy bank and spends $5 a week. Liam has $20 in his piggy bank and does chores to earn an extra $4 a week.

jarptica [38.1K]

Answer:

Ava and Liam have the same amount of money at 10th week.

Step-by-step explanation:

Given:

Amount Ava has in her piggy bank = $110

Amount spends per week = $5

Let the number of weeks be 'w'.

So we can say that.

Total amount Ava had after 'w' weeks = $110-5w$

Also Given:

Amount Liam has in her piggy bank = $20

Amount earns per week = $4

Let the number of weeks be 'w'.

So we can say that.

Total amount Liam had after 'w' weeks = $20+4w$

Now we need to find the number of weeks when both will have same amount.

So we can say that;

Total amount Ava had after 'w' weeks =Total amount Liam had after 'w' weeks

$110-5w=20+4w$

Combining like terms we get;

$110-20=5w+4w\\\\90=9w$

Dividing both side by 9 we get;

$\frac{90}{9}=\frac{9w}{9}\\\\w=10\ weeks$

Hence Ava and Liam have the same amount of money at 10th week.

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4 years ago

ILLLLLmark brainliest plssssssss heeeelpppp

exis [7]

Answer:

a) (x+2)^2-2

Step-by-step explanation:

write in form of x^2+2ax+a^2

2a=4

a=2

x^2+4x+2^2

we will now convert into the form:

x^2+2ax+a^2=(x+a)^2

substitute the values:

x^2+4x+2^2=(x+2)^2

(x+2)^2-2+2^2

(x+2)^2-2

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3 years ago

Read 2 more answers

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andrew-mc [135]

For the reaction,

$CO(g) + H_2 O(g) = CO_2(g) + H_2(g)$

Initial concentration:

0.1M , 0.1M , 0 , 0

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

(0.1 – x)M , (0.1 – x)M , xM , xM

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

$K_c = \frac{x²}{(0.1 – x)²} = 4.24$

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

a = 3.24, b = -0.848, c = 0.0424

(for quadratic equation ax² + bx+c=0)

$x = \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}$

$= > x = \frac{ - ( - 0.848 \: ± \: \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}$

$= > x = \frac{ - 0.848±0.4118}{6.48}$

$x_1 = \frac{0.848 - 0.4118}{6.48} = 0.067$

$x_2 = \frac{0.848 + 0.4118}{6.48} = 0.194$

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

$[CO_2] [H_2] = x = 0.067M$

$[CO] [H_2 O] = 0.1 - 0.067 = 0.033M$

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3 years ago

How can you get the constant of proportonality

kolbaska11 [484]

The constant of proportionality (k) equals the total price (y) divided by the number of cans (x).

Step-by-step explanation:

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4 years ago