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3 years ago

12

Myras stamp collection consisted of 120 stamps in October by the following March her collection had grown to 138 stamps by how m

uch did her collection increase between October and March

2 answers:

Karolina [17]3 years ago

8 0

The answer is 18. Just take the number that comes later and simply subtract from the original number. EXAMPLE- 138-120=18. Hope this helps.

andrezito [222]3 years ago

4 0

It's 15%. Sorry for being late.

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What is the ratio of the calories Robyn

Elina [12.6K]

Question isn't complete but we make assumptions in order to complete the question and explain

Answer and explanation:

If we are given a table on calories burned by Robyn on weekdays from Monday to Friday and on this table Robyn burnt 500 calories on Monday and burnt 400 calories on Wednesday, then we are required to determine the ratio of calories burnt on Wednesday to calories burnt on Monday:

Calories burnt on Wednesday = 400

Calories burnt on Monday =500

Ratio of calories burnt on Wednesday to calories burnt on Monday =400/500=4/5

Ratio =4:5

5 0

3 years ago

Consider this Data Set: 25.5 26 18.2 15.3 28.5 27 20.7 20.2 26.1 18.2 21.4 17.9 24.3 22.6 19.6 The mean of the data set is? and

jekas [21]

Well start by adding all the numbers together, then divide by how many numbers, which is 15

3 0

3 years ago

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago

HELP PLEASE....I REALLY DONT KNOW WHAT THIS WANTS FROM ME

Mkey [24]

Step-by-step explanation:

Area of the circle=

$\frac{\pi {d}^{2} }{4}$

3.14•(17)²/4

=226.865in²

Area of the rectangle=length•width

=(8•15)in²

=120in²

Area of the shaded portion=Area of the circle-Area of a rectangle

=(226.865-120)in²

=106.865in²

=106.87in² to the nearest hundredth

6 0

3 years ago

Someone pls help me

VLD [36.1K]

Answer:

75 men spent 7 hours or more exercising.

Step-by-step explanation:

If you multiply 300 by 0.67, you get 201. That would be the amount of men. Multiply 300 by 0.37 to get 111, the amount of people who spent less than 7 hours exercising, and subtract it from the 201 men to get 90. Then, multiply 300 by 0.75 to get 225, the amount of women that spent 7 hours or more exercising, and subtract it from 300, which would result in an answer of 75. That's how many men spent 7 hours or more exercising.

7 0

4 years ago