Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Answer:16
Step-by-step explanation:
16
3.5 - 4
6.7 - 7
3.2 - 3
1.7 - 2
Add those up and you get 16
We can do this by subtracting 7x from both sides, getting us:
11y= -7x+10.
We can then divide both sides by 11, giving our final answer:
y = -7/11x+10/11.
Hope this helped!
Answer:
x = 9.7
Step-by-step explanation:
The area of a triangle is A = b * h / 2 where A, b, and h are the area, base and height respectively. We know that A, b, and h equal 47, x, and x respectively so we can write:
47 = x * x / 2
47 = x² / 2
94 = x²
x = ±√94
In context, x can't be negative so the answer is x = √94 = 9.7.
Answer:
For a data set of N elements:
{x₁, x₂, ..., xₙ}
The mean is:
The mean absolute deviation is:
And the population standard deviation is:
In this case, our set has 5 elements, and the set is:
{2, 4, 6, 9, 14}
The mean of this set is:
The mean absolute deviation is:
And the population standard deviation is:
