Question

A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger? (DECIMAL FORM)

Answer 1

Answer:

0.07

Step-by-step explanation:

First, add up all the numbers. This will be the denominator.

4+2+3=9

There are 9 pieces of candy.

Since you are randomly choosing two times you will have to multiply two fractions.

There are $\frac{2}{9}$ M&M's, and $\frac{1}{3}$ Butterfingers (You simplify)

Now you multiply these.

$\frac{2}{9}$×$\frac{1}{3}$=$\frac{2}{27}$

Now make this into a decimal. To do this divide 2 and 27. which is approximately 0.07.