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2 years ago

8

32b) What are the like terms in the expression 4y + 5 + 3y? *

1 answer:

pashok25 [27]2 years ago

3 0

Answer:

4y and 3y

Step-by-step explanation:

4y and 3y are like terms because they have y after the number. Every time when a math problem ask you to combine like terms, it'll be the ones that have the same variables or powers.

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I need to know the answer please…

Triss [41]

Answer is a= 51/7 or 7 2/7

Step by step

-2/3 (a + 3) = 5/3a - 19

Distribute to resolve parentheses

-2/3a -2 = 5/3a - 19

Now to move variables to one side
Add 2/3a to both sides

-2/3a + 2/3a -2 = 5/3a + 2/3a -19

Combine like terms

-2 = 7/3a -19

Add 19 to both sides to isolate variable

-2 +19 = 7/3a -19 + 19

17 = 7/3a

Divide both sides by 7/3 to solve for a
(Remember when you divide a fraction, flip it and multiply.)

17 * 3/7 = a

51/7 = a

Picture attached shows steps in order, I think that is what you also needed?

5 0

8 months ago

The larger of two numbers is one more than 3 times the smaller. Eight times the smaller decreased by

Zina [86]

L# = 1 + 3S#
8S# - 2L# = 10

8S# - 2(1 + 3S#) = 10
8S# - 2 + 6S# = 10
14S# = 12
S# = 6/7

L# = 1 + 3(12/14)
L# = 25/7

4 0

2 years ago

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

2 years ago

----<br>--1434........3<br>-57-3 -2 -11<br>2+<br>-----3.+....<br>www

Gnoma [55]

Answer:

Step-by-step explanation:

124

3 0

2 years ago

Addison is going to invest in an account paying an interest rate of 3.1% compounded continuously. How much would Addison need to

professor190 [17]

Answer: $521

Step-by-step explanation:

7 0

3 years ago