Question

the relationship between the relative size of an earthquake, S, and the measure of the earthquake on the Richter scale, R, is given by the equation log S = R. If an earthquake measured 3.2 on the Richter scale, what was it relative size? Express your answer to the nearest hundredth

Answer 1

Answer:

Relative Size, S, is 1584.89

Step-by-step explanation:

The equation is $R=log_{10}(S)$

Where,

• R is the measurement in Richter Scale
• S is the relative size of the earthquare

It is given that in Richter Scale, an earthquake measured 3.2, so $R=3.2$.

They want to know relative size, S, so we put given information in equation and solve for S:

$R=log_{10}(S)\\3.2=log_{10}(S)$

Converting to exponential form, we have:

$3.2=log_{10}(S)\\S=10^{3.2}\\S=1584.8932$

Rounding to nearest hundredth, we have:

$S=1584.89$