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melisa1 [442]
3 years ago
7

I'm really having trouble simplifying trigonometric expressions, I understand the identities, but sometimes I get stuck, and rea

lly need an explanation
sint + tan t
________
tan t
Mathematics
1 answer:
Karolina [17]3 years ago
8 0
\bf \cfrac{sin(t)+tan(t)}{tan(t)}\impliedby \textit{distributing the denominator}
\\\\\\
\cfrac{sin(t)}{tan(t)}+\cfrac{tan(t)}{tan(t)}\implies \cfrac{sin(t)}{\frac{sin(t)}{cos(t)}}+1\implies 
\cfrac{\frac{sin(t)}{1}}{\frac{sin(t)}{cos(t)}}+1
\\\\\\
\cfrac{sin(t)}{1}\cdot \cfrac{cos(t)}{sin(t)}+1\implies cos(t)+1
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Hey can anybody help me with this question please
lakkis [162]
First find average
(5+5+5+5+7+9)/6=6
now see how much they each are differnt
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
5 to 6 is 1
7 to 6 is 1
9 to 6 is 3

average those
(1+1+1+1+1+3)/6=8/6=4/3=1.333

answer is 1.33


 
4 0
3 years ago
In how many ways can the letter of word number taken two at a time
Nitella [24]

Answer:

So the number of ways of choosing two distinct letters at a time is (42)=6. We can then add the duplicate pairs which are O,O and N,N to give a total of 8 possible pairs.

3 0
3 years ago
Read 2 more answers
Shoe size and grade point average
sergey [27]

Answer:

Mild correlation.

Step-by-step explanation:

Girls tend to have smaller feet and so smaller shoe sizes and they tend to score better at school.

7 0
3 years ago
Simplify 2(x + y) + 3(x + y)
ANTONII [103]
The answer would be 5x+5y
5 0
3 years ago
"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim
iren [92.7K]

Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that  since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

5 0
3 years ago
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