For this case we must solve the following equation:

If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
![\sqrt [3] {x ^ 3} = \sqrt [3] {22}\\x = \sqrt [3] {22}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7Bx%20%5E%203%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%5C%5Cx%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D)
That is the exact solution of the equation. Its decimal solution is given by:
![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
ANswer:
The solution to the equation is ![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
Answer:
5.023 I believe
Step-by-step explanation:
Step-by-step explanation:
4k - 6 < 3k + (k - 1)
4k < 3k + 6(k - 1)
4k < 3k + 6k - 6
4k < 9k - 6
4k - 9k < -6
-5k < -6
k < <u>-</u><u>6</u>
-5
k < <u>6</u>
5
All of them are even numbers. You will not find a power of 4 that is an odd number. Also, all of the numbers have a 4 or a 6 or both. For example,
4^3= 64
4^8= <span>65536
I hope this helps:)</span>